Substituting in (1), Sum = [10^6 (10^6 + 1)]/2 = [10^6.10^6 + 10^6]/2. So if we sum that up the number 1-99 will contain 36 + 70 + 74 8= 854 letters. For example:
Sum of first 5 natural numbers is 15. Difference between the sum of even and sum of odd numbers from 1 to 1000 is 500. . For example, 342 (three hundred and forty-two) contains 23 letters and 115 (one hundred and fifteen) contains 20 letters. , 1999. For each number between 1 and 499 there is a corresponding
500500 is a sum of number series from 1 to 1000 by applying the values of input parameters in the formula. step 2 apply the input parameter values in the formulaSum = n/2 x (a + Tn)= 1000/2 x (1 + 1000) = 1001000/2 1 + 2 + 3 + 4 + . 1000*(1000+1)/2=500500, sum of n natural numbers = n(n+1)/2
are known as natural numbers. I have attached my … NOTE: Do not count spaces or hyphens. sum = n*(n+1)/2; cout<<"Sum of first "<

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